:nth-of-type()
        
        
          
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      This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.
The :nth-of-type() CSS pseudo-class matches elements based on their position among siblings of the same type (tag name).
Try it
dt {
  font-weight: bold;
}
dd {
  margin: 3px;
}
dd:nth-of-type(even) {
  border: 2px solid orange;
}
<dl>
  <dt>Vegetables:</dt>
  <dd>1. Tomatoes</dd>
  <dd>2. Cucumbers</dd>
  <dd>3. Mushrooms</dd>
  <dt>Fruits:</dt>
  <dd>4. Apples</dd>
  <dd>5. Mangos</dd>
  <dd>6. Pears</dd>
  <dd>7. Oranges</dd>
</dl>
Syntax
css
:nth-of-type(<An+B> | even | odd) {
  /* ... */
}
Parameters
The :nth-of-type() pseudo-class is specified with a single argument, which represents the pattern for matching elements.
See :nth-child for a more detailed explanation of its syntax.
Examples
>Basic example
HTML
html
<div>
  <div>This element isn't counted.</div>
  <p>1st paragraph.</p>
  <p class="fancy">2nd paragraph.</p>
  <div>This element isn't counted.</div>
  <p class="fancy">3rd paragraph.</p>
  <p>4th paragraph.</p>
</div>
CSS
css
/* Odd paragraphs */
p:nth-of-type(2n + 1) {
  color: red;
}
/* Even paragraphs */
p:nth-of-type(2n) {
  color: blue;
}
/* First paragraph */
p:nth-of-type(1) {
  font-weight: bold;
}
/* This will match the 3rd paragraph as it will match elements which are 2n+1 AND have a class of fancy.
The second paragraph has a class of fancy but is not matched as it is not :nth-of-type(2n+1) */
p.fancy:nth-of-type(2n + 1) {
  text-decoration: underline;
}
Result
Note:
There is no way to select the nth-of-class using this selector. The selector looks at the type only when creating the list of matches. You can however apply CSS to an element based on :nth-of-type location and a class, as shown in the example above.
Specifications
| Specification | 
|---|
| Selectors Level 4> # nth-of-type-pseudo>  | 
            
Browser compatibility
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