yield*
Baseline Widely available
This feature is well established and works across many devices and browser versions. It’s been available across browsers since September 2016.
The yield*
operator can be used within generator (sync or async) functions to delegate to another iterable object, such as a Generator
. Inside async generator functions, it can additionally be used to delegate to another async iterable object, such as an AsyncGenerator
.
Try it
Syntax
yield* expression
Parameters
expression
Optional-
An iterable object.
Return value
Returns the value returned by that iterator when it's closed (when done
is true
).
Description
The yield*
expression iterates over the operand and yields each value returned by it. It delegates iteration of the current generator to an underlying iterator — which we will refer to as "generator" and "iterator", respectively. yield*
first gets the iterator from the operand by calling the latter's [Symbol.iterator]()
method. Then, each time the next()
method of the generator is called, yield*
calls the iterator's next()
method, passing the argument received by the generator's next()
method (always undefined
for the first call), and yielding the same result object as what's returned from the iterator's next()
method. If the iterator result has done: true
, then the yield*
expression stops executing and returns the value
of that result.
The yield*
operator forwards the current generator's throw()
and return()
methods to the underlying iterator as well. If the current generator is prematurely closed through one of these methods, the underlying iterator will be notified. If the generator's throw()
/return()
method is called, the throw()
/return()
method of the underlying iterator is called with the same argument. The return value of throw()
/return()
is handled like the next()
method's result, and if the method throws, the exception is propagated from the yield*
expression.
If the underlying iterator doesn't have a return()
method, the yield*
expression turns into a return
statement, just like calling return()
on a suspended yield
expression.
If the underlying iterator doesn't have a throw()
method, this causes yield*
to throw a TypeError
– but before throwing the error, the underlying iterator's return()
method is called if one exists.
Examples
Delegating to another generator
In following code, values yielded by g1()
are returned from
next()
calls just like those which are yielded by g2()
.
function* g1() {
yield 2;
yield 3;
yield 4;
}
function* g2() {
yield 1;
yield* g1();
yield 5;
}
const gen = g2();
console.log(gen.next()); // {value: 1, done: false}
console.log(gen.next()); // {value: 2, done: false}
console.log(gen.next()); // {value: 3, done: false}
console.log(gen.next()); // {value: 4, done: false}
console.log(gen.next()); // {value: 5, done: false}
console.log(gen.next()); // {value: undefined, done: true}
Other Iterable objects
Besides generator objects, yield*
can also yield
other kinds
of iterables (e.g., arrays, strings, or arguments
objects).
function* g3(...args) {
yield* [1, 2];
yield* "34";
yield* args;
}
const gen = g3(5, 6);
console.log(gen.next()); // {value: 1, done: false}
console.log(gen.next()); // {value: 2, done: false}
console.log(gen.next()); // {value: "3", done: false}
console.log(gen.next()); // {value: "4", done: false}
console.log(gen.next()); // {value: 5, done: false}
console.log(gen.next()); // {value: 6, done: false}
console.log(gen.next()); // {value: undefined, done: true}
The value of yield* expression itself
yield*
is an expression, not a statement, so it evaluates to a value.
function* g4() {
yield* [1, 2, 3];
return "foo";
}
function* g5() {
const g4ReturnValue = yield* g4();
console.log(g4ReturnValue); // 'foo'
return g4ReturnValue;
}
const gen = g5();
console.log(gen.next()); // {value: 1, done: false}
console.log(gen.next()); // {value: 2, done: false}
console.log(gen.next()); // {value: 3, done: false} done is false because g5 generator isn't finished, only g4
console.log(gen.next()); // {value: 'foo', done: true}
Use with async generators
async function* g1() {
await Promise.resolve(0);
yield "foo";
}
function* g2() {
yield "bar";
}
async function* g3() {
// Can use yield* on both async and sync iterators
yield* g1();
yield* g2();
}
const gen = g4();
console.log(await gen.next()); // {value: "foo", done: false}
console.log(await gen.next()); // {value: "bar", done: false}
console.log(await gen.next()); // {done: true}
Method forwarding
The next()
, throw()
, and return()
methods of the current generator are all forwarded to the underlying iterator.
const iterable = {
[Symbol.iterator]() {
let count = 0;
return {
next(v) {
console.log("next called with", v);
count++;
return { value: count, done: false };
},
return(v) {
console.log("return called with", v);
return { value: "iterable return value", done: true };
},
throw(v) {
console.log("throw called with", v);
return { value: "iterable thrown value", done: true };
},
};
},
};
function* gf() {
yield* iterable;
return "gf return value";
}
const gen = gf();
console.log(gen.next(10));
// next called with undefined; the argument of the first next() call is always ignored
// { value: 1, done: false }
console.log(gen.next(20));
// next called with 20
// { value: 2, done: false }
console.log(gen.return(30));
// return called with 30
// { value: 'iterable return value', done: true }
console.log(gen.next(40));
// { value: undefined, done: true }; gen is already closed
const gen2 = gf();
console.log(gen2.next(10));
// next called with undefined
// { value: 1, done: false }
console.log(gen2.throw(50));
// throw called with 50
// { value: 'gf return value', done: true }
console.log(gen.next(60));
// { value: undefined, done: true }; gen is already closed
If the return()
/throw()
method of the underlying iterator returns done: false
, the current generator continues executing and yield*
continues to delegate to the underlying iterator.
const iterable = {
[Symbol.iterator]() {
let count = 0;
return {
next(v) {
console.log("next called with", v);
count++;
return { value: count, done: false };
},
return(v) {
console.log("return called with", v);
return { value: "iterable return value", done: false };
},
};
},
};
function* gf() {
yield* iterable;
return "gf return value";
}
const gen = gf();
console.log(gen.next(10));
// next called with undefined
// { value: 1, done: false }
console.log(gen.return(20));
// return called with 20
// { value: 'iterable return value', done: false }
console.log(gen.next(30));
// { value: 2, done: false }; gen is not closed
If the underlying iterator doesn't have a throw()
method and the generator's throw()
is called, yield*
throws an error.
const iterable = {
[Symbol.iterator]() {
let count = 0;
return {
next(v) {
count++;
return { value: count, done: false };
},
};
},
};
function* gf() {
yield* iterable;
return "gf return value";
}
const gen = gf();
gen.next(); // First next() starts the yield* expression
gen.throw(20); // TypeError: The iterator does not provide a 'throw' method.
Specifications
Specification |
---|
ECMAScript Language Specification # sec-generator-function-definitions-runtime-semantics-evaluation |
Browser compatibility
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