The HTMLElement.offsetTop read-only property returns the distance of the current element relative to the top of the offsetParent node.
Syntax
topPos = element.offsetTop;
Parameters
topPosis the number of pixels from the top of the closest relatively positioned parent element.
Example
var d = document.getElementById("div1");
var topPos = d.offsetTop;
if (topPos > 10) {
// object is offset more
// than 10 pixels from its parent
}
Specification
| Specification | Status | Comment |
|---|---|---|
| CSS Object Model (CSSOM) View Module The definition of 'offsetTop' in that specification. |
Working Draft |
Browser compatibility
We're converting our compatibility data into a machine-readable JSON format. This compatibility table still uses the old format, because we haven't yet converted the data it contains. Find out how you can help!
| Feature | Chrome | Edge | Firefox (Gecko) | Internet Explorer | Opera | Safari (WebKit) |
|---|---|---|---|---|---|---|
| Basic support | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) | (Yes) |
| Feature | Android | Android Webview | Edge | Firefox Mobile (Gecko) | Firefox OS | IE Mobile | Opera Mobile | Safari Mobile | Chrome for Android |
|---|---|---|---|---|---|---|---|---|---|
| Basic support | ? | (Yes) | (Yes) | ? | ? | ? | ? | ? | (Yes) |
In compliance with the specification, this property will return null on Webkit if the element is hidden (the style.display of this element or any ancestor is "none") or if the style.position of the element itself is set to "fixed".
This property will return null on Internet Explorer (9) if the style.position of the element itself is set to "fixed". (Having display:none does not affect this browser.)