Array.of()

The Array.of() method creates a new Array instance from a variable number of arguments, regardless of number or type of the arguments.

The difference between Array.of() and the Array constructor is in the handling of integer arguments: Array.of(7) creates an array with a single element, 7, whereas Array(7) creates an empty array with a length property of 7 (Note: this implies an array of 7 empty slots, not slots with actual undefined values).

Array.of(7);       // [7] 
Array.of(1, 2, 3); // [1, 2, 3]

Array(7);          // [ , , , , , , ]
Array(1, 2, 3);    // [1, 2, 3]

Syntax

Array.of(element0[, element1[, ...[, elementN]]])

Parameters

elementN

Elements of which to create the array.

Return value

A new Array instance.

Description

This function is part of the ECMAScript 2015 standard. For more information see Array.of and Array.from proposal and Array.of polyfill.

Examples

Array.of(1);         // [1]
Array.of(1, 2, 3);   // [1, 2, 3]
Array.of(undefined); // [undefined]

Polyfill

Running the following code before any other code will create Array.of() if it's not natively available.

if (!Array.of) {
  Array.of = function() {
    return Array.prototype.slice.call(arguments);
  };
}

Specifications

Browser compatibility

See also

• Array
• Array.from()
• TypedArray.of()