Object.prototype.hasOwnProperty()
The hasOwnProperty() method returns a boolean indicating
whether the object has the specified property as its own property (as opposed to
inheriting it).
Syntax
hasOwnProperty(prop)Parameters
Return value
A Boolean indicating whether or not the object has the specified property
as own property.
Description
All descendants of Object inherit the hasOwnProperty method.
This method can be used to determine whether an object has the specified property as a
direct property of that object; unlike the in operator,
this method does not check for a property in the object's prototype chain. If an
Object is an Array, hasOwnProperty method can
check whether an index exists.
Note
hasOwnProperty returns true even if the value of the property is
null or undefined.
o = new Object();
o.propOne = null;
o.hasOwnProperty('propOne'); // returns true
o.propTwo = undefined;
o.hasOwnProperty('propTwo'); // returns true
Examples
Using hasOwnProperty to test for a property's existence
The following example determines whether the o object contains a property
named prop:
o = new Object();
o.hasOwnProperty('prop'); // returns false
o.prop = 'exists';
o.hasOwnProperty('prop'); // returns true
Direct vs. inherited properties
The following example differentiates between direct properties and properties inherited through the prototype chain:
o = new Object();
o.prop = 'exists';
o.hasOwnProperty('prop'); // returns true
o.hasOwnProperty('toString'); // returns false
o.hasOwnProperty('hasOwnProperty'); // returns false
Iterating over the properties of an object
The following example shows how to iterate over the properties of an object without
executing on inherited properties. Note that the for...in loop is already only iterating enumerable items, so one should not assume
based on the lack of non-enumerable properties shown in the loop that
hasOwnProperty itself is confined strictly to enumerable items (as with
Object.getOwnPropertyNames()).
var buz = {
fog: 'stack'
};
for (var name in buz) {
if (buz.hasOwnProperty(name)) {
console.log('this is fog (' +
name + ') for sure. Value: ' + buz[name]);
}
else {
console.log(name); // toString or something else
}
}
Using hasOwnProperty as a property name
JavaScript does not protect the property name hasOwnProperty; thus, if the
possibility exists that an object might have a property with this name, it is necessary
to use an external hasOwnProperty to get correct results:
var foo = {
hasOwnProperty: function() {
return false;
},
bar: 'Here be dragons'
};
foo.hasOwnProperty('bar'); // always returns false
// Use another Object's hasOwnProperty
// and call it with 'this' set to foo
({}).hasOwnProperty.call(foo, 'bar'); // true
// It's also possible to use the hasOwnProperty property
// from the Object prototype for this purpose
Object.prototype.hasOwnProperty.call(foo, 'bar'); // true
Note that in the last case there are no newly created objects.
Specifications
| Specification |
|---|
| ECMAScript Language Specification (ECMAScript) # sec-object.prototype.hasownproperty |
Browser compatibility
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