A Function object's read-only name property indicates the function's name as specified when it was created, or it may be either anonymous or '' (an empty string) for functions created anonymously.

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Property attributes of
Writable no
Enumerable no
Configurable yes

Note: In non-standard, pre-ES2015 implementations the configurable attribute was false as well.


The function's name property can be used to identify the function in debugging tools or error messages. It has no semantic significance to the language itself.

The name property is read-only and cannot be changed by the assignment operator:

function someFunction() {} = 'otherFunction';
console.log(; // someFunction

To change it, use Object.defineProperty().

The name property is typically inferred from how the function is defined. In the following sections, we will describe the various ways in which it can be inferred.

Function declaration

The name property returns the name of a function declaration.

function doSomething() {}; // "doSomething"

Default-exported function declaration

An export default declaration exports the function as a declaration instead of an expression. If the declaration is anonymous, the name is "default".

// -- someModule.js --
export default function () {};

// -- main.js --
import someModule from "./someModule.js";; // "default"

Function constructor

Functions created with the Function() constructor have name "anonymous".

new Function().name; // "anonymous"

Function expression

If the function expression is named, that name is used as the name property.

const someFunction = function someFunctionName() {};; // "someFunctionName"

Anonymous function expressions created using the keyword function or arrow functions would have "" (an empty string) as their name.

(function () {}).name; // ""
(() => {}).name; // ""

However, such cases are rare — usually, in order to refer to the expression elsewhere, the function expression is attached to an identifier when it's created (such as in a variable declaration). In such cases, the name can be inferred, as the following few subsections demonstrate.

One practical case where the name cannot be inferred is a function returned from another function:

function getFoo() {
  return () => {};
getFoo().name; // ""

Variable declaration and method

Variables and methods can infer the name of an anonymous function from its syntactic position.

const f = function () {};
const object = {
  someMethod: function () {}

console.log(; // "f"
console.log(; // "someMethod"

The same applies to assignment:

let f;
f = () => {};; // "f"

Initializer and default value

Functions in initializers (default values) of destructuring, default parameters, class fields, etc., will inherit the name of the bound identifier as their name.

const [f = () => {}] = [];; // "f"

const { someMethod: m = () => {} } = {};; // "m"

function foo(f = () => {}) {
foo(); // "f"

class Foo {
  static someMethod = () => {};
}; // someMethod

Shorthand method

const o = {
  foo() {},
};; // "foo";

Bound function

Function.prototype.bind() produces a function whose name is "bound " plus the function name.

function foo() {};
foo.bind({}).name; // "bound foo"

Getter and setter

When using get and set accessor properties, "get" or "set" will appear in the function name.

const o = {
  get foo() {},
  set foo(x) {},

const descriptor = Object.getOwnPropertyDescriptor(o, "foo");; // "get foo"; // "set foo";


A class's name follows the same algorithm as function declarations and expressions.

class Foo {}; // "Foo"

Warning: JavaScript will set the function's name property only if a function does not have an own property called name. However, classes' static members will be set as own properties of the class constructor function, and thus prevent the built-in name from being applied. See an example below.

Symbol as function name

If a Symbol is used a function name and the symbol has a description, the method's name is the description in square brackets.

const sym1 = Symbol("foo");
const sym2 = Symbol();

const o = {
  [sym1]() {},
  [sym2]() {},

o[sym1].name; // "[foo]"
o[sym2].name; // "[]"

Private property

Private fields and private methods have the hash (#) as part of their names.

class Foo {
  #field = () => {};
  #method() {}
  getNames() {

new Foo().getNames();
// "#field"
// "#method"


Telling the constructor name of an object

You can use to check the "class" of an object.

function Foo() {}  // Or: class Foo {}

const fooInstance = new Foo();
console.log(; // logs "Foo"

However, because static members will become own properties of the class, we can't obtain the class name for virtually any class with a static method property name():

class Foo {
  constructor() {}
  static name() {}

With a static name() method no longer holds the actual class name but a reference to the name() function object. Trying to obtain the class of fooInstance via won't give us the class name at all, but instead a reference to the static class method. Example:

const fooInstance = new Foo();
console.log(; // logs function name()

Due to the existence of static fields, name may not be a function either.

class Foo {
  static name = 123;
console.log(new Foo(); // 123

If a class has a static property called name, it will also become writable. The built-in definition in the absence of a custom static definition is read-only: = 'Hello';
console.log(; // logs "Hello" if class Foo has a static name() property but "Foo" if not.

Therefore you may not rely on the built-in name property to always hold a class's name.

JavaScript compressors and minifiers

Warning: Be careful when using the name property with source-code transformations, such as those carried out by JavaScript compressors (minifiers) or obfuscators. These tools are often used as part of a JavaScript build pipeline to reduce the size of a program prior to deploying it to production. Such transformations often change a function's name at build time.

Source code such as:

function Foo() {};
const foo = new Foo();

if ( === 'Foo') {
  console.log("'foo' is an instance of 'Foo'");
} else {

may be compressed to:

function a() {};
const b = new a();
if ( === 'Foo') {
  console.log("'foo' is an instance of 'Foo'");
} else {

In the uncompressed version, the program runs into the truthy branch and logs "'foo' is an instance of 'Foo'" — whereas, in the compressed version it behaves differently, and runs into the else branch. If you rely on the name property, like in the example above, make sure your build pipeline doesn't change function names, or don't assume a function has a particular name.


ECMAScript Language Specification
# sec-function-instances-name

Browser compatibility

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See also

  • A polyfill for functions' .name property is available in core-js
  • Function