String.prototype.indexOf()

The indexOf() method returns the index within the calling String object of the first occurrence of the specified value, starting the search at fromIndex. Returns -1 if the value is not found.

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Syntax

str.indexOf(searchValue)
str.indexOf(searchValue, fromIndex)

Parameters

searchValue

A string representing the value to search for. If no string is explicitly provided, searchValue will be coerced to "undefined" and this value will be searched for in the current string.

fromIndex Optional

An integer representing the index at which to start the search; the default value is 0. For fromIndex values lower than 0 or greater than str.length, the search starts at index 0 and str.length respectively.

Return value

The index of the first occurrence of searchValue, or -1 if not found.
An empty string searchValue will match at any index between 0 and str.length

Description

Characters in a string are indexed from left to right. The index of the first character is 0, and the index of the last character of a string called stringName is stringName.length - 1.

'Blue Whale'.indexOf('Blue');     // returns  0
'Blue Whale'.indexOf('Blute');    // returns -1
'Blue Whale'.indexOf('Whale', 0); // returns  5
'Blue Whale'.indexOf('Whale', 5); // returns  5
'Blue Whale'.indexOf('Whale', 7); // returns -1
'Blue Whale'.indexOf('');         // returns  0
'Blue Whale'.indexOf('', 9);      // returns  9
'Blue Whale'.indexOf('', 10);     // returns 10
'Blue Whale'.indexOf('', 11);     // returns 10

The indexOf() method is case sensitive. For example, the following expression returns -1:

'Blue Whale'.indexOf('blue'); // returns -1

Checking occurrences

Note that '0' doesn't evaluate to true and '-1' doesn't evaluate to false. Therefore, when checking if a specific string exists within another string the correct way to check would be:

'Blue Whale'.indexOf('Blue') !== -1; // true
'Blue Whale'.indexOf('Bloe') !== -1; // false

Examples

Using indexOf()

The following example uses indexOf() to locate values in the string "Brave new world".

const str = 'Brave new world';

console.log('Index of first w from start is ' + str.indexOf('w'));  // logs 8
console.log('Index of "new" from start is ' + str.indexOf('new'));  // logs 6

indexOf() and case-sensitivity

The following example defines two string variables. The variables contain the same string except that the second string contains uppercase letters. The first console.log() method displays 19. But because the indexOf() method is case sensitive, the string "cheddar" is not found in myCapString, so the second console.log() method displays -1.

const myString    = 'brie, pepper jack, cheddar';
const myCapString = 'Brie, Pepper Jack, Cheddar';

console.log('myString.indexOf("cheddar") is ' + myString.indexOf('cheddar'));
// logs 19
console.log('myCapString.indexOf("cheddar") is ' + myCapString.indexOf('cheddar'));
// logs -1

Using indexOf() to count occurrences of a letter in a string

The following example sets count to the number of occurrences of the letter e in the string str:

const str = 'To be, or not to be, that is the question.';
let count = 0;
let position = str.indexOf('e');

while (position !== -1) {
  count++;
  position = str.indexOf('e', position + 1);
}

console.log(count); // displays 4

Specifications

Browser compatibility

See also

• String.prototype.charAt()
• String.prototype.lastIndexOf()
• String.prototype.includes()
• String.prototype.split()
• Array.prototype.indexOf()