Set.prototype.delete()
Baseline Widely available
This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.
The delete() method of Set instances removes a specified value from this set, if it is in the set.
Try it
const set1 = new Set();
set1.add({ x: 10, y: 20 }).add({ x: 20, y: 30 });
// Delete any point with `x > 10`.
set1.forEach((point) => {
if (point.x > 10) {
set1.delete(point);
}
});
console.log(set1.size);
// Expected output: 1
Syntax
js
setInstance.delete(value)
Parameters
value-
The value to remove from
Set.
Return value
Returns true if value was already in
Set; otherwise false.
Examples
Using the delete() method
js
const mySet = new Set();
mySet.add("foo");
console.log(mySet.delete("bar")); // false; no "bar" element found to be deleted.
console.log(mySet.delete("foo")); // true; successfully removed.
console.log(mySet.has("foo")); // false; the "foo" element is no longer present.
Deleting an object from a set
Because objects are compared by reference, you have to delete them by checking individual properties if you don't have a reference to the original object.
js
const setObj = new Set(); // Create a new set.
setObj.add({ x: 10, y: 20 }); // Add object in the set.
setObj.add({ x: 20, y: 30 }); // Add object in the set.
// Delete any point with `x > 10`.
setObj.forEach((point) => {
if (point.x > 10) {
setObj.delete(point);
}
});
Specifications
| Specification |
|---|
| ECMAScript® 2026 Language Specification # sec-set.prototype.delete |