Set.prototype.delete()
The delete() method removes a specified value from a
Set object, if it is in the set.
Try it
Syntax
delete(value)
Parameters
value-
The value to remove from
Set.
Return value
Returns true if value was already in
Set; otherwise false.
Examples
Using the delete() method
const mySet = new Set();
mySet.add('foo');
mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true. Successfully removed.
mySet.has('foo'); // Returns false. The "foo" element is no longer present.
Deleting an object from a set
Because objects are compared by reference, you have to delete them by checking individual properties if you don't have a reference to the original object.
const setObj = new Set(); // Create a new set.
setObj.add({ x: 10, y: 20 }); // Add object in the set.
setObj.add({ x: 20, y: 30 }); // Add object in the set.
// Delete any point with `x > 10`.
setObj.forEach((point) => {
if (point.x > 10) {
setObj.delete(point);
}
});
Specifications
| Specification |
|---|
| ECMAScript Language Specification # sec-set.prototype.delete |
Browser compatibility
BCD tables only load in the browser