Set.prototype.delete()

The delete() method of Set instances removes a specified value from this set, if it is in the set.

Try it

Syntax

js
setInstance.delete(value)

Parameters

value

The value to remove from Set.

Return value

Returns true if value was already in Set; otherwise false.

Examples

Using the delete() method

js
const mySet = new Set();
mySet.add("foo");

console.log(mySet.delete("bar")); // false; no "bar" element found to be deleted.
console.log(mySet.delete("foo")); // true; successfully removed.

console.log(mySet.has("foo")); // false; the "foo" element is no longer present.

Deleting an object from a set

Because objects are compared by reference, you have to delete them by checking individual properties if you don't have a reference to the original object.

js
const setObj = new Set(); // Create a new set.

setObj.add({ x: 10, y: 20 }); // Add object in the set.

setObj.add({ x: 20, y: 30 }); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach((point) => {
  if (point.x > 10) {
    setObj.delete(point);
  }
});

Specifications

Specification
ECMAScript Language Specification
# sec-set.prototype.delete

Browser compatibility

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See also