Set.prototype.delete()

The delete() method removes the specified element from a Set object.

Syntax

mySet.delete(value);

Parameters

value
The value to remove from mySet.

Return value

Returns true if value was successfully removed from mySet; otherwise false.

Examples

Using the delete() method

const mySet = new Set();
mySet.add('foo');

mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true.  Successfully removed.

mySet.has('foo');    // Returns false. The "foo" element is no longer present.

Let's checkout below how to delete an Object from a Set.

const setObj = new Set();   // Create a New Set.

setObj.add({x: 10, y: 20}); // Add object in the set.

setObj.add({x: 20, y: 30}); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function(point){
  if (point.x > 10){
    setObj.delete(point)
  }
})

Specifications

Specification
ECMAScript Latest Draft (ECMA-262)
The definition of 'Set.prototype.delete' in that specification.

Browser compatibility

Update compatibility data on GitHub
DesktopMobileServer
ChromeEdgeFirefoxInternet ExplorerOperaSafariAndroid webviewChrome for AndroidFirefox for AndroidOpera for AndroidSafari on iOSSamsung InternetNode.js
deleteChrome Full support 38Edge Full support 12Firefox Full support 13IE Full support 11Opera Full support 25Safari Full support 8WebView Android Full support 38Chrome Android Full support 38Firefox Android Full support 14Opera Android Full support 25Safari iOS Full support 8Samsung Internet Android Full support 3.0nodejs Full support 0.12
Full support 0.12
Full support 0.10
Disabled
Disabled From version 0.10: this feature is behind the --harmony runtime flag.

Legend

Full support  
Full support
User must explicitly enable this feature.
User must explicitly enable this feature.

See also