Set.prototype.delete()

delete() 方法會一個 Set 物件中移除指定元素。

mySet.delete(value);

value

要從 Set 物件中移除的值。

true 如果成功從 Set 物件中移除；反之 false。

var mySet = new Set();
mySet.add('foo');

mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true.  Successfully removed.

mySet.has('foo');    // Returns false. The "foo" element is no longer present.

下方展示了如何從一個 Set 中移除物件。

var setObj = new Set(); // Create a New Set.

setObj.add({x: 10, y: 20}); // Add object in the set.

setObj.add({x: 20, y: 30}); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function(point){
  if(point.x > 10){
    setObj.delete(point)
  }
})

• Set
• Set.prototype.clear()