Iterator.prototype.flatMap()
Limited availability
This feature is not Baseline because it does not work in some of the most widely-used browsers.
The flatMap()
method of Iterator
instances returns a new iterator helper object that takes each element in the original iterator, runs it through a mapping function, and yields elements returned by the mapping function (which are contained in another iterator or iterable).
Syntax
flatMap(callbackFn)
Parameters
callbackFn
-
A function to execute for each element produced by the iterator. It should return an iterator or iterable that yields elements to be yielded by
flatMap()
. Note that unlikeArray.prototype.flatMap()
, you cannot return single non-iterator/iterable values. The function is called with the following arguments:
Return value
A new iterator helper object. The first time the iterator helper's next()
method is called, it calls callbackFn
on the first element produced by the underlying iterator, and the return value, which should be an iterator or iterable, is yielded one-by-one by the iterator helper (like yield*
). The next element is fetched from the underlying iterator when the previous one returned by callbackFn
is completed. When the underlying iterator is completed, the iterator helper is also completed (the next()
method produces { value: undefined, done: true }
).
Exceptions
TypeError
-
Thrown if
callbackFn
returns a non-iterator/iterable value or a string primitive.
Description
flatMap
accepts two kinds of return values from callbackFn
: an iterator or iterable. They are handled in the same way as Iterator.from()
: if the return value is iterable, the [Symbol.iterator]()
method is called and the return value is used; otherwise, the return value is treated as an iterator and its next()
method is called.
[1, 2, 3]
.values()
.flatMap((x) => {
let itDone = false;
const it = {
next() {
if (itDone) {
return { value: undefined, done: true };
}
itDone = true;
return { value: x, done: false };
},
};
switch (x) {
case 1:
// An iterable that's not an iterator
return { [Symbol.iterator]: () => it };
case 2:
// An iterator that's not an iterable
return it;
case 3:
// An iterable iterator is treated as an iterable
return {
...it,
[Symbol.iterator]() {
console.log("Symbol.iterator called");
return it;
},
};
}
})
.toArray();
// Logs "Symbol.iterator called"
// Returns [1, 2, 3]
Examples
Merging maps
The following example merges two Map
objects into one:
const map1 = new Map([
["a", 1],
["b", 2],
["c", 3],
]);
const map2 = new Map([
["d", 4],
["e", 5],
["f", 6],
]);
const merged = new Map([map1, map2].values().flatMap((x) => x));
console.log(merged.get("a")); // 1
console.log(merged.get("e")); // 5
This avoids creating any temporary copies of the map's content. Note that the array [map1, map2]
must first be converted to an iterator (using Array.prototype.values()
), because Array.prototype.flatMap()
only flattens arrays, not iterables.
new Map([map1, map2].flatMap((x) => x)); // Map(1) {undefined => undefined}
Returning strings
Strings are iterable, but flatMap()
specifically rejects string primitives returned from callbackFn
, this is because the behavior of iterating by code points is often not what you want.
[1, 2, 3]
.values()
.flatMap((x) => String(x))
.toArray(); // TypeError: Iterator.prototype.flatMap called on non-object
You may want to wrap it in an array instead so the entire string is yielded as one:
[1, 2, 3]
.values()
.flatMap((x) => [String(x)])
.toArray(); // ['1', '2', '3']
Or, if the behavior of iterating by code points is intended, you can use Iterator.from()
to convert it to a proper iterator:
[1, 2, 3]
.values()
.flatMap((x) => Iterator.from(String(x * 10)))
.toArray();
// ['1', '0', '2', '0', '3', '0']
Specifications
Specification |
---|
Iterator Helpers # sec-iteratorprototype.flatmap |
Browser compatibility
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