String.prototype.padStart()
        
        
          
                Baseline
                
                  Widely available
                
                
              
        
        
        
          
                
              
                
              
                
              
        
        
      
      This feature is well established and works across many devices and browser versions. It’s been available across browsers since 2017年4月.
padStart() 方法用另一个字符串填充当前字符串(如果需要会重复填充),直到达到给定的长度。填充是从当前字符串的开头开始的。
尝试一下
const str1 = "5";
console.log(str1.padStart(2, "0"));
// Expected output: "05"
const fullNumber = "2034399002125581";
const last4Digits = fullNumber.slice(-4);
const maskedNumber = last4Digits.padStart(fullNumber.length, "*");
console.log(maskedNumber);
// Expected output: "************5581"
语法
js
padStart(targetLength)
padStart(targetLength, padString)
参数
targetLength- 
当前
str填充后的长度。如果该值小于或等于str.length,则会直接返回当前str。 padString可选- 
用于填充当前
str的字符串。如果padString太长,无法适应targetLength,则会从末尾被截断。默认值为 Unicode“空格”字符(U+0020)。 
返回值
在开头填充 padString 直到达到给定的 targetLength 所形成的 String。
示例
>简单示例
js
"abc".padStart(10); // "       abc"
"abc".padStart(10, "foo"); // "foofoofabc"
"abc".padStart(6, "123465"); // "123abc"
"abc".padStart(8, "0"); // "00000abc"
"abc".padStart(1); // "abc"
将数字转换为固定长度的字符串
js
// JavaScript version of: (unsigned)
// printf "%0*d" width num
function leftFillNum(num, targetLength) {
  return num.toString().padStart(targetLength, "0");
}
const num = 123;
console.log(leftFillNum(num, 5)); // "00123"
规范
| Specification | 
|---|
| ECMAScript® 2026 Language Specification> # sec-string.prototype.padstart>  | 
            
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