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TypeError: variable "x" redeclares argument (Firefox)

Error type

TypeError warning in strict mode only.

What went wrong?

The same variable name occurs as a function parameter and is then redeclared using a var assignment in a function body again. This might be a naming conflict and thus JavaScript warns about it.

This error occurs as a warning in strict mode code only. In non-strict code, the redeclaration is silently ignored.


Invalid cases

In this case, the variable "arg" redeclares the argument.

'use strict';

function f(arg) { 
  var arg = 'foo'; 

Valid cases

To fix this warning, the var statement can just be omitted, because the variable exists already. In other cases, you might to rename either the function parameter or the variable name.

'use strict';

function f(arg) {
  arg = 'foo';

See also

Etiquetas y colaboradores del documento

 Colaboradores en esta página: nmve, fscholz
 Última actualización por: nmve,