TypedArray.prototype.sort()

compareFn Optional

A function that defines the sort order. The return value should be a number whose sign indicates the relative order of the two elements: negative if a is less than b, positive if a is greater than b, and zero if they are equal. NaN is treated as 0. The function is called with the following arguments:

a

The first element for comparison. Will never be undefined.

b

The second element for comparison. Will never be undefined.

If omitted, the typed array elements are sorted according to numeric value.

The reference to the original typed array, now sorted. Note that the typed array is sorted in place, and no copy is made.

See Array.prototype.sort() for more details. This method is not generic and can only be called on typed array instances.

For more examples, see also the Array.prototype.sort() method.

let numbers = new Uint8Array([40, 1, 5, 200]);
numbers.sort();
// Uint8Array [ 1, 5, 40, 200 ]
// Unlike plain Arrays, a compare function is not required
// to sort the numbers numerically.

// Regular Arrays require a compare function to sort numerically:
numbers = [40, 1, 5, 200];
numbers.sort();
// [1, 200, 40, 5]

numbers.sort((a, b) => a - b); // compare numbers
// [ 1, 5, 40, 200 ]

• Polyfill of TypedArray.prototype.sort with modern behavior like stable sort in core-js
• JavaScript typed arrays guide
• TypedArray
• TypedArray.prototype.reverse()
• TypedArray.prototype.toSorted()
• Array.prototype.sort()